Jupyter NotebookDownloadsDownload2.3. Neovisnost događajaP(2)=136P(2) = \frac{1}{36}P(2)=361(1)P(3)=P((I,II))+P((II,I))=P(I)⋅P(II)+P(II)⋅P(I)=16⋅16+16⋅16=136+136=118\begin{aligned} P(3) = P((I, II)) + P((II, I)) = P(I) \cdot P(II) + P(II) \cdot P(I) = \frac{1}{6} \cdot \frac{1}{6} + \frac{1}{6} \cdot \frac{1}{6} = \frac{1}{36} + \frac{1}{36} = \frac{1}{18} \end{aligned}P(3)=P((I,II))+P((II,I))=P(I)⋅P(II)+P(II)⋅P(I)=61⋅61+61⋅61=361+361=181(2)AI Centar LipikVjerojatnostAI Centar LipikDistribucije